document.write( "Question 7157: Find a value for X in he equation
\n" ); document.write( "2log10X+3 = log10X+log10 500\r
\n" ); document.write( "\n" ); document.write( "i'm assured the second line is\r
\n" ); document.write( "\n" ); document.write( " $\"+log10x%5E2+\"$ +log10 1000 = log10X+log10 500\r
\n" ); document.write( "\n" ); document.write( "How do you get that from above, i tried using my calculator but it kept giving me errors. \n" ); document.write( "

Algebra.Com's Answer #3949 by prince_abubu(198) $\"\"$ $\"About$

You can put this solution on YOUR website!
The second line is right. It's good to use the log property log a + log b = log (ab). So, the equation then would be:\r
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\n" ); document.write( "\n" ); document.write( " $\"+log%2810%2C1000x%5E2%29+=+log%2810%2C500x%29+\"$ <---- Both logs are base 10, and so you can just set whatever you're finding the log of equal to each other:\r
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\n" ); document.write( "\n" ); document.write( " $\"+1000x%5E2+=+500x+\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"+1000x%5E2+-+500x+=+0+\"$ <--- move 500x to the left\r
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\n" ); document.write( "\n" ); document.write( " $\"+500x%282x+-+1%29+=+0+\"$ <---- Just by looking at this x=0 or x=1/2. We would throw out the x=0 because you can't find the log of 0. (If you have, for example $\"+log%2810%2C0%29=x+\"$ , that would translate to the exponential form $\"+10%5Ex+=+0+\"$ . And there is no such number for x that will make $\"+10%5Ex+\"$ zero.) \n" ); document.write( "

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