document.write( "Question 627221: Eva is 10 years older than Feni. In 8 years, twice Eva's age will equal to three times Feni's age. How old is each at present. \n" ); document.write( "
Algebra.Com's Answer #394898 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Eva is 10 years older than Feni. In 8 years, twice Eva's age will equal to three times Feni's age. How old is each at present \n" ); document.write( "Let \n" ); document.write( "Present age of Eva = e years old \n" ); document.write( "Present age of Feni = f years old\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Eva is 10 years older than Feni. \n" ); document.write( "e=f+10..............(1) \n" ); document.write( "In 8 years, \n" ); document.write( "Eva will be = e+8 \n" ); document.write( "Feni will be = f+8 \n" ); document.write( "Then \n" ); document.write( "Twice Eva's age will equal to three times Feni's age \n" ); document.write( "2(e+8)=3(f+8) \n" ); document.write( "2e+16=3f+24 \n" ); document.write( "2e=3f+24-16 \n" ); document.write( "2e=3f+8..............(2) \n" ); document.write( "Substitute the value of e from (1) to (2)\r \n" ); document.write( "\n" ); document.write( "2e=3f+8 \n" ); document.write( "2(f+10)=3f+8 \n" ); document.write( "2f+20=3f+8 \n" ); document.write( "2f-3f=8-20 \n" ); document.write( "-f=-12 \n" ); document.write( "Multiply by -1 both sides \n" ); document.write( "f=12 \n" ); document.write( "Put the value of f in (1)\r \n" ); document.write( "\n" ); document.write( "e=f+10..............(1)\r \n" ); document.write( "\n" ); document.write( "e=12+10 \n" ); document.write( "e=22\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Present age of Eva = e = 22 years old \n" ); document.write( "Present age of Feni = f = 12 years old \n" ); document.write( " \n" ); document.write( " |