document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=627347>Question 627347</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My ages are: 10,50,26. How do I get those to add up to 150? What's the equation if it is even possible? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #394883 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=394883\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Currently they add up to 10+50+26 = 86\r<BR>\n" );
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document.write( "If you add x years to each age, then you get 10+x, 50+x, and 26+x\r<BR>\n" );
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document.write( "Add up the ages and force that result to be 150. Then solve for x. \r<BR>\n" );
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document.write( "(10+x)+(50+x)+(26+x) = 150\r<BR>\n" );
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document.write( "10+x+50+x+26+x = 150\r<BR>\n" );
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document.write( "3x+86 = 150\r<BR>\n" );
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document.write( "3x = 150-86\r<BR>\n" );
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document.write( "3x = 64\r<BR>\n" );
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document.write( "x = 64/3\r<BR>\n" );
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document.write( "x = 21.333\r<BR>\n" );
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document.write( "So there isn't a whole number of years that can pass by where your three ages add to 150.\r<BR>\n" );
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