document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=627330>Question 627330</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many committes of 4 can be formed from 20 Republicans and 15 Democrats if at least 1 Republican and at least 1 Democrat must be on the committee? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #394882 by </B><A HREF=/tutors/aboutme.mpl?userid=psbhowmick><B>psbhowmick(878)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=psbhowmick><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=psbhowmick><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=394882\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Combinations possible in the committee<BR>\n" );
document.write( "a) 1 Republican + 3 Democrats: 20C1 x 15C3 = 20 x (13x14x15)/(2x3) = 9100<BR>\n" );
document.write( "b) 2 Republican + 2 Democrats: 20C2 x 15C2 = (19x20)/2 x (14x15)/2 = 19950<BR>\n" );
document.write( "c) 3 Republican + 1 Democrats: 20C3 x 15C1 = (18x19x20)/(2x3) x 15 = 17100\r<BR>\n" );
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document.write( "Total number of such committees possible is: a + b + c = 46150. </SPAN>\n" );
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