document.write( "Question 627310: how much pure acid should be mixed with 5 gallons of a 30% acid solution in order to get a 50% acid solution? \n" ); document.write( "
Algebra.Com's Answer #394848 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "how much pure acid\"highlight%28x%29\" should be mixed with 5 gallons of a 30% acid solution
\n" ); document.write( "in order to get a 50% acid solution?
\n" ); document.write( " acid + acid = acid
\n" ); document.write( " \"x+%2B++.30%2A5gal+=+.50%285%2Bx%29\"
\n" ); document.write( " \"+.5x+=+.20%2A5\"
\n" ); document.write( " x = 2 gal\r
\n" ); document.write( "\n" ); document.write( "Note: 2gal + 1.5gal = 3.5gal
\n" ); document.write( "Set Up on ALL mixture problems is to have the same amount of the key ingredient on both sides of the EQ \n" ); document.write( "
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