document.write( "Question 627125: On his drive from Montpelier, Vermont to Columbia, South Carolina, Victor averaged 51 mph. If he had been able to average 60 mph, he would have reached his destination 3 hrs earlier. What is the driving distance between Montpelier and Columbia? \n" ); document.write( "

Algebra.Com's Answer #394771 by josmiceli(19441) $\"\"$ $\"About$

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Driving 51 mi/hr average:
\n" ); document.write( "(1) $\"+d+=+51t+\"$
\n" ); document.write( "Driving 60 mi/hr average:
\n" ); document.write( "(2) $\"+d+=+60%2A%28+t+-+3+%29+\"$
\n" ); document.write( "------------------------
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) $\"+51t+=+60%2A%28+t+-+3+%29+\"$
\n" ); document.write( "(2) $\"+51t+=+60t+-+180+\"$
\n" ); document.write( "(2) $\"+9t+=+180+\"$
\n" ); document.write( "(2) $\"+t+=+20+\"$
\n" ); document.write( "and
\n" ); document.write( "(1) $\"+d+=+51t+\"$
\n" ); document.write( "(1) $\"+d+=+51%2A20+\"$
\n" ); document.write( "(1) $\"+d+=+1020+\"$
\n" ); document.write( "The distance is 1,020 mi
\n" ); document.write( "check:
\n" ); document.write( "(2) $\"+d+=+60%2A%28+t+-+3+%29+\"$
\n" ); document.write( "(2) $\"+1020+=+60%2A%28+20+-+3+%29+\"$
\n" ); document.write( "(2) $\"+1020+=+60%2A17+\"$
\n" ); document.write( "(20 $\"+1020+=+1020+\"$
\n" ); document.write( "OK\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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