document.write( "Question 57787: Can you teach me how to solve this problem.
\n" ); document.write( "The sum of three numbers is 105. The third is 11 less than ten times the second. Twice the first is 7 more than three times the second. Find the numbers. \n" ); document.write( "
Algebra.Com's Answer #39470 by stanbon(75887)\"\" \"About 
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The sum of three numbers is 105. The third is 11 less than ten times the second. Twice the first is 7 more than three times the second. Find the numbers.
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\n" ); document.write( "Notice that the 1st and the 3rd are described in terms of the 2nd.
\n" ); document.write( "So. let the 2nd number be \"x\".
\n" ); document.write( "Then the 3rd is \"10x-11\"\r
\n" ); document.write( "\n" ); document.write( "Since 2(1st)=3x+7, 1st is (1/2)(3x+7)
\n" ); document.write( "EQUATION:
\n" ); document.write( "1st + 2nd + 3rd = 105
\n" ); document.write( "(1/2)(3x+7)+x+10x-11=105
\n" ); document.write( "(3/2)x+(7/2)+11x-11=105
\n" ); document.write( "(25/2)x=112.50
\n" ); document.write( "25x=225
\n" ); document.write( "x=9 (this is the 2nd number)
\n" ); document.write( "3rd number is 10x-11=79
\n" ); document.write( "1st number is (1/2)(3*9+7)=17
\n" ); document.write( "Cheers,
\n" ); document.write( "stan H.
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