document.write( "Question 627090: Given that f(x) has real coefficients and x=k is a zero, what other number must be a zero? Have no idea how to go about this. Please help me.\r
\n" ); document.write( "\n" ); document.write( " k=3- \"+sqrt%282%29+\"
\n" ); document.write( " k=1+i \"+sqrt%285%29+\"
\n" ); document.write( " k= \"+sqrt%282%29\" + i \"+sqrt%287%29+\"
\n" ); document.write( "k=i
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Algebra.Com's Answer #394677 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Both irrational and complex roots come in conjugate pairs given a polynomial equation with real coefficients.\r
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\n" ); document.write( "\n" ); document.write( "If you have an irrational root of the form , then must also be a root. If you have a complex root of the form , then must also be a root. Hint: \r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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\"The

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