document.write( "Question 627085: Solve the equation on the interval [0,2pi] for sin^2 theta-cos theta=4. What is the solution set? \n" ); document.write( "
Algebra.Com's Answer #394665 by stanbon(75887)\"\" \"About 
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Solve the equation on the interval [0,2pi] for
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\n" ); document.write( "sin^2 theta-cos theta = 4
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\n" ); document.write( "Substitute for sin^2
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\n" ); document.write( "1-cos^2(x) - cos(x) = 4
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\n" ); document.write( "Rearrange
\n" ); document.write( "cos^2+cos+3 = 0
\n" ); document.write( "cos = [-1 +- sqrt(1-4*3)]/2
\n" ); document.write( "cos = [-1 +- sqrt(-11)]/2
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\n" ); document.write( "Note: The cos values are complex numbers.
\n" ); document.write( "No Real Number solution for theta.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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