document.write( "Question 57776This question is from textbook Hawkes Intermediate Algebra
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document.write( ": Ok, this is my question and actually this might be too late but I am struggling and I need this to be turned in by 11:59 P.M. so that gives me 1 hour to get this question. It is...\r
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document.write( "x-2/4-x - 7/2x+1 = 0
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document.write( "I just did this problem but w/out the =0 and we just had to Simplify and got 2(x^2+2x-15)/5x+4 but I am unsure how to solve for x? If you could help me out as soon as possible that would be GREAT...thank you so much!\r
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document.write( "You can e-mail me at Zoe228@aol.com and I will respond faster, THANKS! \n" );
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Algebra.Com's Answer #39461 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! Given: x - 2/4*x - 7/2*x + 1 = 0.\r \n" ); document.write( "\n" ); document.write( "This simplifies to x - 1/2*x - 7/2*x + 1 = 0.\r \n" ); document.write( "\n" ); document.write( "Or x - 8/2*x + 1 = 0.\r \n" ); document.write( "\n" ); document.write( "Or x - 4x + 1 = 0.\r \n" ); document.write( "\n" ); document.write( "Or -3x + 1 = 0.\r \n" ); document.write( "\n" ); document.write( "That means -3x has to = -1 for the equation to = 0.\r \n" ); document.write( "\n" ); document.write( "So x is simply 1/3. \n" ); document.write( " \n" ); document.write( " |