document.write( "Question 626967: use completing the square to discribe the graph of f(x)=36-12x-x^2
\n" ); document.write( "support your answer graphically \n" ); document.write( "
Algebra.Com's Answer #394559 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
use completing the square to describe the graph of f(x)=36-12x-x^2
\n" ); document.write( "f(x) = 0
\n" ); document.write( "0 = 36 - 12x - x^2
\n" ); document.write( "x^2 + 12x + ___ = 36
\n" ); document.write( "Complete the square; (12/2)^2 = 36, add to both sides
\n" ); document.write( "x^2 + 12x + 36 = 36 + 36
\n" ); document.write( "x^2 + 12x + 36 = 72
\n" ); document.write( "(x + 6)^2 = 72
\n" ); document.write( "x + 6 = +/-\"sqrt%2872%29\"
\n" ); document.write( "extract the square root of 36
\n" ); document.write( "x + 6 = +/-\"6sqrt%282%29\"
\n" ); document.write( "Two solutions
\n" ); document.write( "x = \"-6+%2B+6sqrt%282%29\"
\n" ); document.write( "and
\n" ); document.write( "x = \"-6+-+6sqrt%282%29\"
\n" ); document.write( ";
\n" ); document.write( "support your answer graphically
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-20%2C+20%2C+-80%2C+50%2C+x%5E2%2B12x-36%29+\"
\n" ); document.write( ":
\n" ); document.write( "\"-6+%2B+6sqrt%282%29\" ~ +2.5
\n" ); document.write( "\"-6+-+6sqrt%282%29\" ~ -14.5 \n" ); document.write( "
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