document.write( "Question 626936: Please help me with this problem :)) thanks,
\n" ); document.write( "a car runs 10 km an hiur faster than a jeepney. Find the rate of each if the car can travel 200 km one hour less than that if the jeepney.
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Algebra.Com's Answer #394536 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
a car runs 10 km an hour faster than a jeepney. Find the rate of each if the car can travel 200 km one hour less than that of the jeepney.
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\n" ); document.write( "Car DATA:
\n" ); document.write( "rate = x kmh ; distance = 200 km ; time = d/r = 200/x hrs.
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\n" ); document.write( "Jeep DATA:
\n" ); document.write( "rate = x-10 kmh ; distance = 200 km ; time = d/r = 200/(x-10) hrs
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\n" ); document.write( "Equation:
\n" ); document.write( "jeep time - car time = 1 hour
\n" ); document.write( "200/(x-10) - 200/x = 1
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\n" ); document.write( "Multiply thru by x(x-10) to get:
\n" ); document.write( "200x - 200(x-10) = x(x-10)
\n" ); document.write( "2000 = x^2-10x
\n" ); document.write( "x^2-10x-2000 = 0
\n" ); document.write( "(x-50)(x+40) = 0
\n" ); document.write( "x = 50 kmh (rate of the car
\n" ); document.write( "x-10 = 40 kmh (rate of the jeep)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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