document.write( "Question 626936: Please help me with this problem :)) thanks,
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document.write( "a car runs 10 km an hiur faster than a jeepney. Find the rate of each if the car can travel 200 km one hour less than that if the jeepney. \n" );
document.write( "
Algebra.Com's Answer #394536 by stanbon(75887) ![]() You can put this solution on YOUR website! a car runs 10 km an hour faster than a jeepney. Find the rate of each if the car can travel 200 km one hour less than that of the jeepney. \n" ); document.write( "--------- \n" ); document.write( "Car DATA: \n" ); document.write( "rate = x kmh ; distance = 200 km ; time = d/r = 200/x hrs. \n" ); document.write( "------------------ \n" ); document.write( "Jeep DATA: \n" ); document.write( "rate = x-10 kmh ; distance = 200 km ; time = d/r = 200/(x-10) hrs \n" ); document.write( "--- \n" ); document.write( "Equation: \n" ); document.write( "jeep time - car time = 1 hour \n" ); document.write( "200/(x-10) - 200/x = 1 \n" ); document.write( "--- \n" ); document.write( "Multiply thru by x(x-10) to get: \n" ); document.write( "200x - 200(x-10) = x(x-10) \n" ); document.write( "2000 = x^2-10x \n" ); document.write( "x^2-10x-2000 = 0 \n" ); document.write( "(x-50)(x+40) = 0 \n" ); document.write( "x = 50 kmh (rate of the car \n" ); document.write( "x-10 = 40 kmh (rate of the jeep) \n" ); document.write( "========================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=============== \n" ); document.write( " \n" ); document.write( " |