document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=626939>Question 626939</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1. )Find the length of the diagonal of a rectangle whose sides are 24 cm and 35 cm.<BR>\n" );
document.write( "2.) Solve for the area of a square whose diagonal is 16 &#8730;2 cm long.<BR>\n" );
document.write( "3. What is the area of a right triangle if the hypotenuse is 35 cm and the shorter leg is 21 cm. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #394529 by </B><A HREF=/tutors/aboutme.mpl?userid=psbhowmick><B>psbhowmick(878)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=psbhowmick><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=psbhowmick><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=394529\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Diagonal+=+sqrt%28Length%5E2+%2B+Width%5E2%29=sqrt%2824%5E2%2B35%5E2%29=42.44 ALIGN=MIDDLE  ALT=\"Diagonal+=+sqrt%28Length%5E2+%2B+Width%5E2%29=sqrt%2824%5E2%2B35%5E2%29=42.44\"   DISABLED_style= \"max-width:90%; height:auto;\" ><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+cm ALIGN=MIDDLE  ALT=\"+cm\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "2) Diagonal of the square of side <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a ALIGN=MIDDLE  ALT=\"a\"   DISABLED_style= \"max-width:90%; height:auto;\" > is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%2Asqrt%282%29 ALIGN=MIDDLE  ALT=\"a%2Asqrt%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >. <BR>\n" );
document.write( "If the diagonal of the square is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=16%2Asqrt%282%29 ALIGN=MIDDLE  ALT=\"16%2Asqrt%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > then <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a=16 ALIGN=MIDDLE  ALT=\"a=16\"   DISABLED_style= \"max-width:90%; height:auto;\" >. <BR>\n" );
document.write( "Hence, area of the square is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=16%5E2+=+256 ALIGN=MIDDLE  ALT=\"16%5E2+=+256\"   DISABLED_style= \"max-width:90%; height:auto;\" ><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=cm%5E2 ALIGN=MIDDLE  ALT=\"cm%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "3) Use Pythagoras theorem again, the longer side is 28 cm. </SPAN>\n" );
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