document.write( "Question 626933: Find three consecutive even integers whose sum is 38 more than four times the largest integer. \n" ); document.write( "

Algebra.Com's Answer #394515 by psbhowmick(878) $\"\"$ $\"About$

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Let the consecutive even integers be: (2n-2), 2n and (2n+2).\r
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\n" ); document.write( "\n" ); document.write( "Their sum = $\"%282n-2%29+%2B+2n+%2B+%282n%2B2%29+=+6n\"$
\n" ); document.write( "The largest integer = $\"%282n%2B2%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "By problem i.e. Sum - 4 x Largest Integer = 38
\n" ); document.write( " $\"6n+-+4%282n%2B2%29+=+38\"$
\n" ); document.write( " $\"6n+-+8n+-+8+=+38\"$
\n" ); document.write( " $\"2n+=+-38-8=-46\"$ \r
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\n" ); document.write( "\n" ); document.write( "Thus, the three consecutive integers are: -48, -46 and -44 \n" ); document.write( "

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