\n" ); document.write( "\n" ); document.write( "How many total zeros does the function have?
\n" ); document.write( "Possible real zeros? Possible negative zeros?
Algebra.Com's Answer #394514 by psbhowmick(878)![\"\"](\"/images/stars/stars-11.gif\")  You can put this solution on YOUR website! Every polynomial in one variable of degree n, n > 0, has exactly n real or complex zeros.\r \n" ); document.write( "\n" ); document.write( "Total zeroes = total no. of roots = degree of the polynomial = highest index = 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since the coefficients of the polynomial are real so is there has to be complex roots, that will occur in pairs - at max there can be two pairs of complex and conjugate roots. Hence, there is at least one real root.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To find max no. of negative roots, express f(x) as f(-x).\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The no. of sign changes from the term with highest degree of x to that with lowest degree of x is 4. Thus max. possible no. of negative roots is 4. \n" ); document.write( " |