document.write( "Question 626918: Consider the following sequence of numbers:\r
\n" ); document.write( "\n" ); document.write( "2;4;2;7;2;10;2;13;...\r
\n" ); document.write( "\n" ); document.write( "1.3.1 If the sequence behaves consistently, write down the 12th term of the above sequence?\r
\n" ); document.write( "\n" ); document.write( "1.3.2 Calculate the sum of the first 50 terms of the sequence.
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Algebra.Com's Answer #394499 by psbhowmick(878)\"\" \"About 
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\"t%5B1%5D=2\"
\n" ); document.write( "\"t%5B2%5D=4\"
\n" ); document.write( "\"t%5B3%5D=2\"
\n" ); document.write( "\"t%5B4%5D=7\"
\n" ); document.write( "\"t%5B5%5D=2\"
\n" ); document.write( "\"t%5B6%5D=10\"
\n" ); document.write( "\"t%5B7%5D=2\"
\n" ); document.write( "\"t%5B8%5D=13\"\r
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\n" ); document.write( "\n" ); document.write( "Thus, for n=1,2,3,...,etc. we can write \"t%5B2n-1%5D=2\" and \"t%5B2n%5D=4%2B3%28n-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "Substitute n = 6, the 12th term of the sequence is \"t%5B12%5D=4%2B3%286-1%29=19\"\r
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\n" ); document.write( "\n" ); document.write( "Substitute n = 25, the 12th term of the sequence is \"t%5B50%5D=4%2B3%2825-1%29=76\"
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