document.write( "Question 626826: 2y+x=0
\n" ); document.write( " x=y+9
\n" ); document.write( "Solve by substitution.
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Algebra.Com's Answer #394468 by Maths68(1474)\"\" \"About 
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2y+x=0.......(1)
\n" ); document.write( "x=y+9........(2)
\n" ); document.write( "Substitute the value of x from (2) to (1)
\n" ); document.write( "2y+x=0
\n" ); document.write( "2y+(y+9)=0
\n" ); document.write( "2y+y+9=0
\n" ); document.write( "Subtract 9 from the both sides
\n" ); document.write( "2y+y+9-9=0-9
\n" ); document.write( "3y=-9
\n" ); document.write( "Divide by 3 both sides
\n" ); document.write( "3y/3=-9/3
\n" ); document.write( "y=-3
\n" ); document.write( "Put the value of y in (2)
\n" ); document.write( "x=y+9........(2)
\n" ); document.write( "x=-3+9
\n" ); document.write( "x=6\r
\n" ); document.write( "\n" ); document.write( "x,y=6,-3\r
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\n" ); document.write( "\n" ); document.write( "Check
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\n" ); document.write( "Put the value of x and y in (1)
\n" ); document.write( "2y+x=0.......(1)
\n" ); document.write( "2(-3)+6=0
\n" ); document.write( "-6+6=0
\n" ); document.write( "0=0
\n" ); document.write( "Put the value of x and y in (1)
\n" ); document.write( "x=y+9........(2)
\n" ); document.write( "6=-3+9
\n" ); document.write( "6=6\r
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