document.write( "Question 626855: Hi, may you please help me solve this problem. Thank you :)\r
\n" ); document.write( "\n" ); document.write( "Find the perimeter of the triangle lying in xyz-space with vertices at points (7,2,3), (7, 14,3), and (12, 14, 3).\r
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Algebra.Com's Answer #394465 by reviewermath(1029)\"\" \"About 
You can put this solution on YOUR website!
distance between (7,2,3) and (7,14,3) =\"sqrt%28%287-7%29%5E2+%2B+%282-14%29%5E2+%2B+%283-3%29%5E2%29\"= 12
\n" ); document.write( "distance between (7,2,3) and (12,14,3) =\"sqrt%28%287-12%29%5E2+%2B+%282-14%29%5E2+%2B+%283-3%29%5E2%29\"= 13
\n" ); document.write( "distance between (7,14,3) and (12,14,3) =\"sqrt%28%287-12%29%5E2+%2B+%2814-14%29%5E2+%2B+%283-3%29%5E2%29\"= 5
\n" ); document.write( "Add the 3 distances to get the perimeter
\n" ); document.write( "Perimeter = 12 + 13 + 5 = \"highlight%2830%29\"
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