document.write( "Question 57766: 32. 2w(4w+1)=1\r
\n" ); document.write( "\n" ); document.write( "can someone please help \n" ); document.write( "

Algebra.Com's Answer #39444 by hayek(51) $\"\"$ $\"About$

You can put this solution on YOUR website!
You need to get the quadratic into the form $\"a%2Ax%5E2%2Bb%2Ax%2Bc=0\"$ so it can be factored.
\n" ); document.write( "Problem: $\"2w%284w%2B1%29=1\"$
\n" ); document.write( "Expand the left side first
\n" ); document.write( " $\"2w%2A4w%2B2w=1\"$
\n" ); document.write( " $\"8w%5E2%2B2w=1\"$
\n" ); document.write( "subtract 1 from both sides
\n" ); document.write( " $\"8w%5E2%2B2w-1=0\"$
\n" ); document.write( "Now, factor as usual:
\n" ); document.write( " $\"%284w-1%29%282w%2B1%29=0\"$
\n" ); document.write( "This can be true if:
\n" ); document.write( " $\"4w-1=0\"$ or $\"2w%2B1=0\"$
\n" ); document.write( "So the two factors are:
\n" ); document.write( "w=1/4 or w=-1/2 \n" ); document.write( "

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