document.write( "Question 626772: Please help solve: (r-2)^3 \n" ); document.write( "
Algebra.Com's Answer #394417 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"%28r-2%29%5E3\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28r-2%29%28r-2%29%28r-2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28r-2%29%28r%5E2-4r%2B4%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"r%28r%5E2-4r%2B4%29-2%28r%5E2-4r%2B4%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"r%5E3-4r%5E2%2B4r-2r%5E2%2B8r-8\"\r
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\n" ); document.write( "\n" ); document.write( "\"r%5E3-6r%5E2%2B12r-8\"\r
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\n" ); document.write( "\n" ); document.write( "So \"%28r-2%29%5E3\" expands out to \"r%5E3-6r%5E2%2B12r-8\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"%28r-2%29%5E3=r%5E3-6r%5E2%2B12r-8\" for all values of 'r'\r
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\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you\r
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