document.write( "Question 626740: Given 3x + y = 17 and x + 3y = -1. Find the value of 3x + 3y \n" ); document.write( "
Algebra.Com's Answer #394400 by jim_thompson5910(35256) ![]() You can put this solution on YOUR website! 3x + y = 17 \n" ); document.write( "x + 3y = -1 \n" ); document.write( "------------ \n" ); document.write( "4x+4y = 16\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4x+4y = 16\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4(x+y) = 16\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x+y = 16/4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x+y = 4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3(x+y) = 3*4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3x+3y = 12\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------------------------------------------------------------- \n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Jim \n" ); document.write( "-------------------------------------------------------------------------------------------------------------- \n" ); document.write( " |