document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=626682>Question 626682</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A lorry and a car travel uniformly along expressway from city A to city B . Thw lorry leaves at 915 amd arrives at 1315. The car leaves at 1000 and arrive at 1245. At what time did the car overtake the lorry.? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #394377 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=394377\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> d = r * t  (Distance is rate times time).<P><BR>\n" );
document.write( "Call the lorry's speed L and the car's speed C.<P><BR>\n" );
document.write( "The distance they travel is the same, so 4L = 2.75C<P><BR>\n" );
document.write( "The distance the car must make up in some time (t) is the time of head start the lorry had, times the lorry's speed, which is:  .75L and that equals the car's speed times the time (t) so .75L = Ct<P><BR>\n" );
document.write( "Use the first equation to find L in terms of C.  4L=2.75C so L = 2.75/4 * C = .6875C.<P><BR>\n" );
document.write( "Substitute that into the second equation:<BR>\n" );
document.write( ".75(.6875C) = Ct so .515625C = Ct and .515625 = t = approx 30.9 minutes.\r<BR>\n" );
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