document.write( "Question 626662: the smallestof three consecutives integers is added to twice the largest, the result so obtained is 15 less than four timess the middle integer.find the integers \n" ); document.write( "
Algebra.Com's Answer #394356 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "the smallest of three consecutives integers\"highlight%28x%29\",\"highlight%28x%2B1%29\", \"highlight%28x%2B2%29\"
\n" ); document.write( "is added to twice the largest, the result so obtained is 15 less than four timess the middle integer.
\n" ); document.write( "Question states***
\n" ); document.write( " x + 2(x+2) = 4(x+1) - 15
\n" ); document.write( " 3x + 4 = 4x + 4 - 15
\n" ); document.write( " 15 = x
\n" ); document.write( "The three consecutives integers are 15, 16, 17
\n" ); document.write( "and
\n" ); document.write( " \"15+%2B+2%2A17+=+49+=++4%2A16+-+15\" \n" ); document.write( "
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