document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=626633>Question 626633</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the equation of a straight line where the gradient is -2 through coordinates 1,3. as simple breakdown as possible please its been a long time. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #394335 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=394335\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  what is the equation of a straight line where the gradient is -2 through coordinates 1,3.<BR>\n" );
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document.write( "Equation form: y = mx + b<BR>\n" );
document.write( "Determine \"m\" and \"b\"<BR>\n" );
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document.write( "m = slope = gradient = -2<BR>\n" );
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document.write( "Substitute to find \"b\":<BR>\n" );
document.write( "3 = -2*1 + b<BR>\n" );
document.write( "b = 5<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "y = -2x + 5<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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