document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=57741>Question 57741</A>: <I><SPAN STYLE=\"word-break: break-all;\"> system of linear wquations. solve in substitution or addition method  there is no book  if possible express in ordered pair\r<BR>\n" );
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document.write( "3x-5y=1<BR>\n" );
document.write( "10y=6x-1\r<BR>\n" );
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document.write( "thanks,<BR>\n" );
document.write( "dnn </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #39431 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=39431\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3X-5Y=1<BR>\n" );
document.write( "3X=5Y+1<BR>\n" );
document.write( "X=5Y/3+1/3<BR>\n" );
document.write( "THEN<BR>\n" );
document.write( "10Y=6(5Y/3)+1/3<BR>\n" );
document.write( "10Y=(30Y/3)+1/3<BR>\n" );
document.write( "10Y=10Y+1/3<BR>\n" );
document.write( "10Y-10Y=1/3<BR>\n" );
document.write( "0=1/3<BR>\n" );
document.write( "NO VALID SOLUTIONS FOR X OR Y\r<BR>\n" );
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