document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=626547>Question 626547</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how would I complete the steps? of if cos(t) = 1/4 and 0 < t < pi/2, then cos(pi/6+t) = ???<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #394288 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=394288\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how would I complete the steps? of if cos(t) = 1/4 and 0 < t < pi/2, then cos(pi/6+t) = ???<BR>\n" );
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document.write( "Note: if cos(t) = 1/4, then x = 1 and r = 4<BR>\n" );
document.write( "Therefore y = sqrt(r^2-x^2) = sqrt(16-1) = sqrt(15)<BR>\n" );
document.write( "So sin(t) = y/r = sqrt(15)/4<BR>\n" );
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document.write( "cos((pi/6)+t) = cos(pi/6)*cos(t) - sin(pi/6)*sin(t)<BR>\n" );
document.write( "cos((pi/6)+t) = [sqrt(3)/2]*(1/4) - (1/2)(sqrt(15)/4)<BR>\n" );
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document.write( "= sqrt(3)/8 - sqrt(15)/8<BR>\n" );
document.write( "= (sqrt(3)-sqrt(15))/8<BR>\n" );
document.write( "is approximately -0.2676..<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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