document.write( "Question 626509: For a normal distribution that has a mean of 100 and a standard deviation of 8. Determine the Z-score for each of the following X values:
\n" ); document.write( "X=70 Z=-3.75
\n" ); document.write( "X=124 Z=3\r
\n" ); document.write( "\n" ); document.write( "Use the information in 1 to determine the area or probability of
\n" ); document.write( " p(92 < x < 108)
\n" ); document.write( "p(84 < x < 116)
\n" ); document.write( "p(x < 84) \n" ); document.write( "
Algebra.Com's Answer #394249 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
For a normal distribution that has a mean of 100 and a standard deviation of 8. Determine the Z-score for each of the following X values:
\n" ); document.write( "X=70 Z=-3.75
\n" ); document.write( "X=124 Z=3
\n" ); document.write( "Use the information in 1 to determine the area or probability of
\n" ); document.write( "p(92 < x < 108) = ?
\n" ); document.write( "z(92) = (92-100)/8 = -1
\n" ); document.write( "z(108) = (108-100)/8 = 1
\n" ); document.write( "P(92 < x < 108) = P(-1 < z < 1) = 0.6827
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\n" ); document.write( "p(84 < x < 116) = ?
\n" ); document.write( "z(84) = (84-100)/8 = -2
\n" ); document.write( "z(116) = (116-100)/8 = 2
\n" ); document.write( "P(84 < x < 116) = P(-2 < z < 2) = 0.9545
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\n" ); document.write( "p(x < 84) = ?
\n" ); document.write( "z(84) = -2
\n" ); document.write( "P(x < 84) = P(z < -2) = P(-100< z < -2) = 0.0228
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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