document.write( "Question 626508: How many milliliters of a 31% alcohol solution must be added to 6 milliliters of a 11% alcohol solution to produce a 21% alcohol solution? \n" ); document.write( "

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Solution A
\n" ); document.write( "Amount = x ml
\n" ); document.write( "Concentration = 31% = 0.31\r
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\n" ); document.write( "\n" ); document.write( "Solution B
\n" ); document.write( "Amount = 6 ml
\n" ); document.write( "Concentration = 11% = 0.11\r
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\n" ); document.write( "\n" ); document.write( "Mixture
\n" ); document.write( "Amount = 6+x ml
\n" ); document.write( "Concentration = 21% = 0.21\r
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\n" ); document.write( "\n" ); document.write( "(Amount of Solution A)*(Concentration of Solution A)+ (Amount of Solution B)*(Concentration of Solution B)=(Amount of Mixture)*(Concentration of Mixture)
\n" ); document.write( "(x)*(0.31)+ (6)*(0.11)=(6+x)*(0.21)
\n" ); document.write( "0.31x+0.66=1.26+0.21x
\n" ); document.write( "0.31x-0.21x=1.26-0.66
\n" ); document.write( "0.1x=0.6
\n" ); document.write( "0.1x/0.1=0.6/0.1
\n" ); document.write( "x=6\r
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\n" ); document.write( "\n" ); document.write( "6ml of a 31% alcohol solution must be added to 6 ml of a 11% alcohol solution to produce 12ml of a 21% alcohol solution.\r
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