document.write( "Question 626497: Factor x^2 - 19x - 120 \n" ); document.write( "
Algebra.Com's Answer #394221 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Looking at the expression \"x%5E2-19x-120\", we can see that the first coefficient is \"1\", the second coefficient is \"-19\", and the last term is \"-120\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"1\" by the last term \"-120\" to get \"%281%29%28-120%29=-120\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"-120\" (the previous product) and add to the second coefficient \"-19\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"-120\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"-120\":\r
\n" ); document.write( "\n" ); document.write( "1,2,3,4,5,6,8,10,12,15,20,24,30,40,60,120\r
\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-4,-5,-6,-8,-10,-12,-15,-20,-24,-30,-40,-60,-120\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"-120\".\r
\n" ); document.write( "\n" ); document.write( "1*(-120) = -120
\n" ); document.write( "2*(-60) = -120
\n" ); document.write( "3*(-40) = -120
\n" ); document.write( "4*(-30) = -120
\n" ); document.write( "5*(-24) = -120
\n" ); document.write( "6*(-20) = -120
\n" ); document.write( "8*(-15) = -120
\n" ); document.write( "10*(-12) = -120
\n" ); document.write( "(-1)*(120) = -120
\n" ); document.write( "(-2)*(60) = -120
\n" ); document.write( "(-3)*(40) = -120
\n" ); document.write( "(-4)*(30) = -120
\n" ); document.write( "(-5)*(24) = -120
\n" ); document.write( "(-6)*(20) = -120
\n" ); document.write( "(-8)*(15) = -120
\n" ); document.write( "(-10)*(12) = -120\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"-19\":\r
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First NumberSecond NumberSum
1-1201+(-120)=-119
2-602+(-60)=-58
3-403+(-40)=-37
4-304+(-30)=-26
5-245+(-24)=-19
6-206+(-20)=-14
8-158+(-15)=-7
10-1210+(-12)=-2
-1120-1+120=119
-260-2+60=58
-340-3+40=37
-430-4+30=26
-524-5+24=19
-620-6+20=14
-815-8+15=7
-1012-10+12=2
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers \"5\" and \"-24\" add to \"-19\" (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers \"5\" and \"-24\" both multiply to \"-120\" and add to \"-19\"\r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term \"-19x\" with \"5x-24x\". Remember, \"5\" and \"-24\" add to \"-19\". So this shows us that \"5x-24x=-19x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bhighlight%285x-24x%29-120\" Replace the second term \"-19x\" with \"5x-24x\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2%2B5x%29%2B%28-24x-120%29\" Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x%2B5%29%2B%28-24x-120%29\" Factor out the GCF \"x\" from the first group.\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x%2B5%29-24%28x%2B5%29\" Factor out \"24\" from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-24%29%28x%2B5%29\" Combine like terms. Or factor out the common term \"x%2B5\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"x%5E2-19x-120\" factors to \"%28x-24%29%28x%2B5%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"x%5E2-19x-120=%28x-24%29%28x%2B5%29\".\r
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\n" ); document.write( "\n" ); document.write( "Note: you can check the answer by expanding \"%28x-24%29%28x%2B5%29\" to get \"x%5E2-19x-120\" or by graphing the original expression and the answer (the two graphs should be identical).\r
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