document.write( "Question 7131: I am trying to learn, with great difficulty, how to factor this type of problem... 2a^2-2ab-24b^2 ... I have tried factoring out the 2, but I don't know how to go any further with this problem. How do I find the factors of 12 if there is no factor for the prceding term? Thank you so much for your help. \n" ); document.write( "
Algebra.Com's Answer #3942 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Well, you could start by factoring a 2 from the expression, just to simplify it a bit.\r
\n" ); document.write( "\n" ); document.write( "\"2a%5E2+-+2ab+-+24b%5E2\" = \"2%28a%5E2+-+ab+-+12b%5E2%29\"
\n" ); document.write( "Now let's look at the expression in the parentheses: \"a%5E2+-+ab+-+12b%5E2\"
\n" ); document.write( "The factors of the first term , \"a%5E2\" would be \"%28a%29%28a%29\"
\n" ); document.write( "Look at the last term: \"-12b%5E2\" and ask what are the factors of this term?\r
\n" ); document.write( "\n" ); document.write( "\"-12b%5E2\" = \"%283b%29%28-4b%29\" or \"%28-3b%29%284b%29\" just to name a couple.\r
\n" ); document.write( "\n" ); document.write( "So, now try: \"%28a+%2B+3b%29%28a+-+4b%29\" Using the FOIL method, multiply these factors:\r
\n" ); document.write( "\n" ); document.write( "\"%28a+%2B+3b%29%28a+-+4b%29+=+%28a%5E2+-+4ab+%2B+3ab+-+12b%5E2%29\" Simplify to get:
\n" ); document.write( "\"a%5E2+-+ab+-+12b%5E2\" and if you multiply by the 2 we factored at the start, we'll get:\r
\n" ); document.write( "\n" ); document.write( "\"2a%5E2+-+2ab+-+24b%5E2\"\r
\n" ); document.write( "\n" ); document.write( "So, the factors are: \"2%28a%2B3b%29%28a-4b%29\"
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