document.write( "Question 626387: I have looked at many posts of almost the same questions and am confused, the question is: The cost, in millions of dollars, to remove x % of pollution in a lake is modeled by the equation 6000/200-2x. what is the cost to remove %75,%90,%99. First off shouldn't the percentages be converted to decimal? Then, do I divide 6000 by 200 first or should I multiply 2* the percentage first? Any change will offer the wrong answer. \n" ); document.write( "

Algebra.Com's Answer #394153 by Alan3354(69443) $\"\"$ $\"About$

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I have looked at many posts of almost the same questions and am confused, the question is: The cost, in millions of dollars, to remove x % of pollution in a lake is modeled by the equation 6000/200-2x. what is the cost to remove %75,%90,%99. First off shouldn't the percentages be converted to decimal? Then, do I divide 6000 by 200 first or should I multiply 2* the percentage first? Any change will offer the wrong answer.
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\n" ); document.write( "6000/200-2x
\n" ); document.write( "The equation can be made to use the %, or the decimal value
\n" ); document.write( "6000/200-200x using the decimal value would give the same result.
\n" ); document.write( "And, it's 6000/(200-2x), just sloppiness on the part of the presenter, or the author.
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\n" ); document.write( "75%: C = 6000/(200 - 150) = 120 million
\n" ); document.write( "etc \n" ); document.write( "

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