document.write( "Question 626408: The length of a rectangle is 2 feet more that its width. Find the dimensions of the rectangle if its area is 63 square feet. Show your work using a quadratic equation to solve. \n" ); document.write( "
Algebra.Com's Answer #394147 by nerdybill(7384)\"\" \"About 
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The length of a rectangle is 2 feet more that its width. Find the dimensions of the rectangle if its area is 63 square feet. Show your work using a quadratic equation to solve.
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\n" ); document.write( "Let w = width
\n" ); document.write( "then
\n" ); document.write( "w+2 = length
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\n" ); document.write( "w(w+2) = 63
\n" ); document.write( "w^2 + 2w = 63
\n" ); document.write( "w^2 + 2w - 63 = 0
\n" ); document.write( "(w+9)(w-7) = 0
\n" ); document.write( "w = {-9, 7}
\n" ); document.write( "throw out the negative solution leaving
\n" ); document.write( "w = 7 feet (width)
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\n" ); document.write( "Length:
\n" ); document.write( "w+2 = 7+2 = 9 feet
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\n" ); document.write( "Answer: 7 feet by 9 feet \n" ); document.write( "
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