document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=626403>Question 626403</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the exact solution, using common logarithms, and a two-decimal-place approximation, when appropriate.\r<BR>\n" );
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document.write( "log(x^(2)+6)-log(x+1)=2+log(x-1)\r<BR>\n" );
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document.write( "x=<BR>\n" );
document.write( "x~ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #394145 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=394145\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the exact solution, using common logarithms, and a two-decimal-place approximation, when appropriate. <BR>\n" );
document.write( "log(x^(2)+6)-log(x+1)=2+log(x-1)<BR>\n" );
document.write( "log(x^(2)+6)-log(x+1)-log(x-1)=2<BR>\n" );
document.write( "log(x^(2)+6)-[log(x+1)+log(x-1)]=2<BR>\n" );
document.write( "place under single log<BR>\n" );
document.write( "log[(x^2+6)/((x+1)(x-1))]=2<BR>\n" );
document.write( "convert to exponential form<BR>\n" );
document.write( "10^2=(x^2+6)/((x+1)(x-1))=100<BR>\n" );
document.write( "(x^2+6)/((x+1)(x-1))=100<BR>\n" );
document.write( "(x^2+6)/(x^2-1)=100<BR>\n" );
document.write( "x^2+6=100x^2-100<BR>\n" );
document.write( "99x^2-106=0<BR>\n" );
document.write( "x^2=106/99<BR>\n" );
document.write( "x=±&#8730;(106/99)<BR>\n" );
document.write( "x&#8776;-1.04(reject, x>1)<BR>\n" );
document.write( "or<BR>\n" );
document.write( "x&#8776;1.04 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );