document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=626389>Question 626389</A>: <I><SPAN STYLE=\"word-break: break-all;\"> complete the following proof related to the figure below. \r<BR>\n" );
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document.write( "the figure is a triangle with a line down the middle, the top is labeled T, angle on the right is S, angle on the left is R and the bottom of the segment that goes through the middle is labeled Q.\r<BR>\n" );
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document.write( "Given: segment TQ bisects angles RTS, angle R=angles S    Prove: segment TQ is perpendicular segment RS  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #394137 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=394137\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
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document.write( "The sum of the measures of the internal angles of all triangles is 180, so since mRTQ = mSTQ (defn bisector) and mR = mS (given), mRQT = mSQT (set up an equation and use Transitive Equality.  But RQS is a straight angle and mRQS = mRQT + mSQT.  The defn of a straight angle and a little algebra says that mRQT = mSQT = 90 degrees.  Hence  TQ <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \perp\"> RS by defn perpendicular. \r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi}\ +\ 1\ =\ 0\"><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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