document.write( "Question 626260: Two investments totaling $32,000 produce an annual income of $1,070. One investment yields 3% a year, while the other yields 5% per year. How much is invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #394101 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! (.05x)+.03(32000-x)=1070 \n" ); document.write( ".05x+960-.03x=1070 \n" ); document.write( ".02x=1070-960 \n" ); document.write( ".02x=110 \n" ); document.write( "x=110/.02 \n" ); document.write( "x=5500 amount invested @ 5%. \n" ); document.write( "32000-5500=26500 amount invested @ 3%. \n" ); document.write( "Proof: \n" ); document.write( ".05*5500+.03*26500=1070 \n" ); document.write( "275+785=1070 \n" ); document.write( "1070=1070 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |