document.write( "Question 626260: Two investments totaling $32,000 produce an annual income of $1,070. One investment yields 3% a year, while the other yields 5% per year. How much is invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #394101 by checkley79(3341)\"\" \"About 
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(.05x)+.03(32000-x)=1070
\n" ); document.write( ".05x+960-.03x=1070
\n" ); document.write( ".02x=1070-960
\n" ); document.write( ".02x=110
\n" ); document.write( "x=110/.02
\n" ); document.write( "x=5500 amount invested @ 5%.
\n" ); document.write( "32000-5500=26500 amount invested @ 3%.
\n" ); document.write( "Proof:
\n" ); document.write( ".05*5500+.03*26500=1070
\n" ); document.write( "275+785=1070
\n" ); document.write( "1070=1070
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