document.write( "Question 626225: This graph of a function is a translation of y = 2/x . What is an equation for the function?\r
\n" ); document.write( "\n" ); document.write( "A. y = 2/(x - 3) – 5\r
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Algebra.Com's Answer #394063 by Edwin McCravy(20065)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Translation Rules:\r\n" );
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document.write( "1. To translate a graph of an equation RIGHT by K units replace x by (x - K)\r\n" );
document.write( "   in the equation.\r\n" );
document.write( "2. To translate a graph of an equation LEFT by K units replace x by (x + K)\r\n" );
document.write( "   in the equation.\r\n" );
document.write( "3. To translate a graph of an equation UP by K units add +K to the right side\r\n" );
document.write( "   of the equation.\r\n" );
document.write( "4. To translate a graph of an equation DOWN by K units add -K to the right side\r\n" );
document.write( "   of the equation.\r\n" );
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document.write( "A.  y = 2/(x - 3) – 5\r\n" );
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document.write( "Here, in y = 2/x, the x has been replaced by (x - 3) and -5 has been added to\r\n" );
document.write( " the right side, so the graph of y = 2/x has been translated 3 units RIGHT\r\n" );
document.write( "and 5 units DOWN. \r\n" );
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document.write( "B.  y = 2/(x – 5) – 3\r\n" );
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document.write( "Here, in y = 2/x, the x has been replaced by (x - 5) and -3 has been added to\r\n" );
document.write( " the right side, so the graph of y = 2/x has been translated 5 units RIGHT\r\n" );
document.write( "and 3 units DOWN.\r\n" );
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document.write( "C.  y = 2/(x – 3) + 5\r\n" );
document.write( "\r\n" );
document.write( "Here, in y = 2/x, the x has been replaced by (x - 3) and +5 has been added to\r\n" );
document.write( " the right side, so the graph of y = 2/x has been translated 3 units RIGHT\r\n" );
document.write( "and 5 units UP.\r\n" );
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document.write( "Edwin
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