document.write( "Question 626209: Find the equation of the line containing (4,-3)that is parallel to the line 6x-4y=1 \n" ); document.write( "
Algebra.Com's Answer #394032 by nerdybill(7384)\"\" \"About 
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Find the equation of the line containing (4,-3)that is parallel to the line 6x-4y=1
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\n" ); document.write( "slope of:
\n" ); document.write( "6x-4y=1
\n" ); document.write( "-4y=-6x+1
\n" ); document.write( "4y=6x-1
\n" ); document.write( "y=(6/4)x-1/4
\n" ); document.write( "y=(3/2)x-1/4
\n" ); document.write( "slope is 3/2
\n" ); document.write( "a parallel line must have the same slope.
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\n" ); document.write( "Now, we have the slope (3/2) and one point (4,-3)
\n" ); document.write( "plug into \"point-slope\" form:
\n" ); document.write( "y - y1 = m(x - x1)
\n" ); document.write( "y - (-3) = (3/2)(x - 4)
\n" ); document.write( "y + 3 = (3/2)x - (3/2)4
\n" ); document.write( "y + 3 = (3/2)x - (3)2
\n" ); document.write( "y + 3 = (3/2)x - 6
\n" ); document.write( "y = (3/2)x - 9\r
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