document.write( "Question 625941: The probabilities that a batch of 4 computers will contain 0,1,2,3, and 4 defective computers are 0.6274, 0.3102, 0.0575, 0.0047, and 0.0001, respectfully. Find the standard deviation for the probability distribution. \n" ); document.write( "
Algebra.Com's Answer #393928 by Theo(13342)\"\" \"About 
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this is what i understand this to be:
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document.write( "x	p(x)	        p(x)*x	      (x-mean)^2	(x-mean)^2*p(x)\r\n" );
document.write( "0	0.6274	        0	      0.19333609	0.121299063\r\n" );
document.write( "1	0.3102	        0.3102	      0.31393609	0.097382975\r\n" );
document.write( "2	0.0575	        0.115	      2.43453609	0.139985825\r\n" );
document.write( "3	0.0047	        0.0141	      6.55513609	0.03080914\r\n" );
document.write( "4	0.0001	        0.0004	      12.67573609	0.001267574\r\n" );
document.write( "				\r\n" );
document.write( "	mean >>>>>	0.4397		\r\n" );
document.write( "			                 variance >>>>	0.390744576\r\n" );
document.write( "			       standard deviation >>>>	0.625095654\r\n" );
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\n" ); document.write( "mean is .4397
\n" ); document.write( "standard deviation is .625095654 which is the square root of the variance.
\n" ); document.write( "mean is calculated as x occurrences times the probability of x occurrences.
\n" ); document.write( "these are then all added up to get the mean.
\n" ); document.write( "variance is calculated as follows:
\n" ); document.write( "first you get x occurrences minus the mean.
\n" ); document.write( "then you square that.
\n" ); document.write( "then you multiply that by the probability of x occurrences
\n" ); document.write( "these are then all added up to get the variance.
\n" ); document.write( "than you take the square root of the variance to get the standard deviation.
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