document.write( "Question 625961: Graph the equation. Identify the center, vertices and Foci.
\n" ); document.write( "\"+%28x%2B3%29%5E2%2F16+-+%28y-1%29%5E2%2F25=1+\"
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Algebra.Com's Answer #393916 by lwsshak3(11628)\"\" \"About 
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Graph the equation. Identify the center, vertices and Foci
\n" ); document.write( "\"%28x%2B3%29%5E2%2F16+-+%28y-1%29%5E2%2F25=1\"
\n" ); document.write( "This is an equation of a hyperbola with horizontal transverse axis.
\n" ); document.write( "Its standard form of equation:\"%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1\"
\n" ); document.write( "For given equation:
\n" ); document.write( "center: (-3,1)
\n" ); document.write( "a^2=16
\n" ); document.write( "a=√16=4
\n" ); document.write( "vertices: (-3±a,1)=(-3±4,1)=(-7,1) and (1,1)
\n" ); document.write( "..
\n" ); document.write( "b^2=25
\n" ); document.write( "b=√25=5
\n" ); document.write( "..
\n" ); document.write( "c^2=a^2+b^2=16+25=41
\n" ); document.write( "c=√41≈6.4
\n" ); document.write( "Foci: (-3±c,1)=(-3±6.4,1)=(-9.4,1) and (3.4,1)
\n" ); document.write( "see graph below:
\n" ); document.write( "y=±(25(x+3)^2/16-25)^.5+1\r
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