document.write( "Question 625915: Can't seem to find any 'solvers\" to check for subtraction, only addition.
\n" ); document.write( "Please help me solve\r
\n" ); document.write( "\n" ); document.write( "y-3x=-4
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Algebra.Com's Answer #393887 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
addition and subtraction are 2 sides of the came coin.
\n" ); document.write( "5 - (+7) = -2
\n" ); document.write( "5 + (-7) = -2\r
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\n" ); document.write( "\n" ); document.write( "y - 3x = -4 is your equation
\n" ); document.write( "apparently you want to solve for y.
\n" ); document.write( "if so, then this is what you do:
\n" ); document.write( "add 3x to both sides of this equation to get:
\n" ); document.write( "y = 3x - 4
\n" ); document.write( "you have just solved for y.
\n" ); document.write( "asuming you had wanted to solve for x instead, this is what you do:
\n" ); document.write( "equation is:
\n" ); document.write( "y - 3x = -4
\n" ); document.write( "subtract y from both sides of the equation to get:
\n" ); document.write( "-3x = -y - 4
\n" ); document.write( "divide both sides of the equation by -3 to get:
\n" ); document.write( "x = y/3 + 4/3
\n" ); document.write( "your 2 equations are:
\n" ); document.write( "y = 3x - 4
\n" ); document.write( "x = y/3 + 4/3
\n" ); document.write( "when x = 1:
\n" ); document.write( "y = 3x - 4 yields y = 3 - 4 = -1
\n" ); document.write( "when y = -1:
\n" ); document.write( "x = y/3 + 4/3 yields x = -1/3 + 4/3 = 3/3 = 1
\n" ); document.write( "the 2 equations are equivalent too each other.
\n" ); document.write( "y = equation solves for given values of x.
\n" ); document.write( "x = equation solves for given values of y.
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