document.write( "Question 625894: A. Graph the function ƒ(x) = x3 - 4x + 2.
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document.write( "B. Find the domain and range of ƒ, showing all work or explaining your rationale.
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document.write( "C. Find the derivative of ƒ, showing all work.
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document.write( "D. Find the slope of the graph of ƒ at x = 0, showing all work.
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document.write( "E. Let ƒ represent the position of an object with respect to time that is moving along a line. Identify when the object is moving in the positive and negative directions and when the object is at rest, showing all work. \n" );
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Algebra.Com's Answer #393867 by AnlytcPhil(1807)  You can put this solution on YOUR website! \r\n" );
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document.write( "f(x)= \r\n" );
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document.write( "Here is the graph:\r\n" );
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document.write( " does not exist because\r\n" );
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document.write( " =  = \r\n" );
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document.write( "Therefore lim, f(x),\r\n" );
document.write( "\"x->1\",\"\" )}}} does not exist because the denominator becomes 0 but the\r\n" );
document.write( "numerator does not become 0, but becomes -1. Therefore, there is a\r\n" );
document.write( "non-removable infinite discontinuity at x=1. That's where ther is a\r\n" );
document.write( "vertical asymptote. \r\n" );
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document.write( " =  = \r\n" );
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document.write( "There is no point at (2,1). However since both numerator and\r\n" );
document.write( "denominator approach 0, the limit might exist and there may be a\r\n" );
document.write( "removable discontinutity there indicated by the small circle on\r\n" );
document.write( "the graph.\r\n" );
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document.write( " =  =  =  =  = = = 1\r\n" );
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document.write( "So the limit exists at 2 and equals 1. However f(2) is not defined.\r\n" );
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document.write( "So there is a removable discontinuity at x=2 \r\n" );
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document.write( "Sometimes this is called \"a hole in the graph\".\r\n" );
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document.write( "So there is a non-removable infinite discontinuity at x=1,\r\n" );
document.write( "and a removable discontinuity at x=2`\r\n" );
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document.write( "Edwin \n" );
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