document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=625855>Question 625855</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of two numbers is 56. one third of the first number plus one fourth of the second number is 16. find the numbers.\r<BR>\n" );
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document.write( "please give solution in variables x and y. use also formula and explain clearly thanks.. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #393828 by </B><A HREF=/tutors/aboutme.mpl?userid=NewtonMathCenter><B>NewtonMathCenter(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=NewtonMathCenter><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=393828\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=first number and y=second number.<BR>\n" );
document.write( "The sum of two numbers is 56 can be represented as x+y=56.<BR>\n" );
document.write( "One third of the first number plus one fourth of the second number is 16 can be written as (1/3)x+(1/4)y=16.  Remember of represents multiplication.<BR>\n" );
document.write( "Now we can solve this system of equations by either substitution or elimination.  I will do elimination.  Thus I will multiply the second equation by 12, the lowest common denominator, to eliminate all of the fractions:)  We then get <BR>\n" );
document.write( "4x+3y=192.  I will now multiply the first equation by -3 so we can add the two equations and eliminate the y variable.  We then get -3x-3y=-168.  Now add the two equations:  <BR>\n" );
document.write( "4x+3y=192<BR>\n" );
document.write( "-3x-3y=-168<BR>\n" );
document.write( "x=24<BR>\n" );
document.write( "To solve for y, substitute the x into any original equation:<BR>\n" );
document.write( "x+y=56<BR>\n" );
document.write( "24+y=56<BR>\n" );
document.write( "y=32  by subtracting 24 from both sides.<BR>\n" );
document.write( "Now you can check your answer:<BR>\n" );
document.write( "24+32=56  yes<BR>\n" );
document.write( "(1/3)24+(1/4)32=16  yes<BR>\n" );
document.write( "Yay:)<BR>\n" );
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