document.write( "Question 625860: \r\n" );
document.write( "
\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( " x-1 x\r\n" );
document.write( "————— + ——————\r\n" );
document.write( " x³ x²+1
Algebra.Com's Answer #393827 by Edwin McCravy(20060)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "\r\n" ); document.write( " x-1 x\r\n" ); document.write( "————— + ——————\r\n" ); document.write( " x³ x²+1\r\n" ); document.write( "\r\n" ); document.write( "The LCD is x³(x²+1), so we multiply each\r\n" ); document.write( "fraction by whichever factor of the LCD its\r\n" ); document.write( "denominator is lacking, over itself.\r\n" ); document.write( "\r\n" ); document.write( "The first fraction's denominator lacks the \r\n" ); document.write( "factor x²+1 and the second fraction's \r\n" ); document.write( "denominator lacks the factor x³, so we put \r\n" ); document.write( "the missing factors over themselves and \r\n" ); document.write( "multiply, so that the denominators will both\r\n" ); document.write( "become the LCD.\r\n" ); document.write( "\r\n" ); document.write( " x-1 x²+1 x x³\r\n" ); document.write( "————— · —————— + —————— · ————\r\n" ); document.write( " x³ x²+1 x²+1 x³\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "(x-1)(x²+1) (x)(x³)\r\n" ); document.write( "——————————— + ———————————— \r\n" ); document.write( " x³(x²+1) (x²+1)(x³)\r\n" ); document.write( "\r\n" ); document.write( " x³+x-x²-1 x4\r\n" ); document.write( "——————————— + ———————————— \r\n" ); document.write( " x³(x²+1) (x²+1)(x³)\r\n" ); document.write( "\r\n" ); document.write( " x³+x-x²-1+x4\r\n" ); document.write( "—————————————— \r\n" ); document.write( " x³(x²+1) \r\n" ); document.write( "\r\n" ); document.write( " x4+x³-x²+x-1\r\n" ); document.write( "—————————————— \r\n" ); document.write( " x³(x²+1)\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |