document.write( "Question 625825: A) 7a+3z=12\r
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document.write( "B) 3a+7z=6\r
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document.write( "Given the formulas above, what is the value of a-z? \n" );
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Algebra.Com's Answer #393807 by nvegupta(2)![]() ![]() ![]() You can put this solution on YOUR website! 7a+3z=12 \n" ); document.write( "7a=12-3z \n" ); document.write( "a=(12-3z)/7\r \n" ); document.write( "\n" ); document.write( "3a+7z=6 \n" ); document.write( "3a=6-7z \n" ); document.write( "a=(6-7z)/3\r \n" ); document.write( "\n" ); document.write( "a=a \n" ); document.write( "(12-3z)/7=(6-7z)/3 \n" ); document.write( "3(12-3z)=7(6-7z) \n" ); document.write( "36-9z=42-49z \n" ); document.write( "-9z+49z=42-36 \n" ); document.write( "40z=6 \n" ); document.write( "z=6/40 \n" ); document.write( "z=3/20\r \n" ); document.write( "\n" ); document.write( "PUT VALUE OF z IN ANY SUITABLE EQUATION TO FIND VALUE OF a.\r \n" ); document.write( "\n" ); document.write( "7a+3z=12 \n" ); document.write( "7a+3*3/20=12 \n" ); document.write( "7a+9/20=12 \n" ); document.write( "7a=12-9/20 \n" ); document.write( "7a=231/20 \n" ); document.write( "a=(231/20)/7 \n" ); document.write( "a=231/140\r \n" ); document.write( "\n" ); document.write( "a-z \n" ); document.write( "=(231/140)-(3/20) \n" ); document.write( "=210/140 \n" ); document.write( "=21/14 \n" ); document.write( "=3/2 \n" ); document.write( " |