document.write( "Question 625796: A solution of 35% glycol is held in a 400 gallon tank. A 72% solution of glycol is held in a 190 gallon tank. How much of the two tanks must be added together to have a 200 gallon tank of 50% glycol? \n" ); document.write( "
Algebra.Com's Answer #393794 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
A solution of 35% glycol is held in a 400 gallon tank. A 72% solution of glycol is held in a 190 gallon tank. How much of the two tanks must be added together to have a 200 gallon tank of 50% glycol?
\n" ); document.write( ".
\n" ); document.write( "Let x = amount (gallons) of 35%
\n" ); document.write( "then
\n" ); document.write( "200-x = amount (gallons) of 72%
\n" ); document.write( ".
\n" ); document.write( ".35x + .72(200-x) = .50(200)
\n" ); document.write( ".35x + 144-.72x = 100
\n" ); document.write( "144-.37x = 100
\n" ); document.write( "-.37x = -44
\n" ); document.write( "x = 118.9 gallons (35% solution)
\n" ); document.write( ".
\n" ); document.write( "72% solution:
\n" ); document.write( "200-x = 200-118.9 = 81.1 gallons
\n" ); document.write( "
\n" ); document.write( "
\n" );