document.write( "Question 57642This question is from textbook Applied College Algebra
\n" ); document.write( ": Find a polynomial function with real coefficients that has zeros 3 and - 4i, has degree 3 and where P(0) = -96. \n" ); document.write( "
Algebra.Com's Answer #39377 by ankor@dixie-net.com(22740)\"\" \"About 
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Find a polynomial function with real coefficients that has zeros 3 and - 4i, has degree 3 and where P(0) = -96.
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\n" ); document.write( "We know one factor is (x-3) = 0
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\n" ); document.write( "x = -4i
\n" ); document.write( "x^2 = (-4i)^2
\n" ); document.write( "x^2 = 16(i^2)
\n" ); document.write( "x^2 = 16(-1)
\n" ); document.write( "x^2 = -16
\n" ); document.write( "x^2 + 16 = 0
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\n" ); document.write( "Factors are: (x-3)(x^2 + 16) = 0
\n" ); document.write( "FOIl this:
\n" ); document.write( "x^3 - 3x^2 + 16x - 48 = 0
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\n" ); document.write( "However is says P(0) = - 96, the last term in our equation is -48:
\n" ); document.write( "Change (x-3) to (2x - 6), we still have a 0 of +3, but if we FOIL this,
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\n" ); document.write( "(2x-6)(x^2 + 16) = 2x^3 - 6x^2 + 32x - 96 = 0
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\n" ); document.write( "This should satisfy the requirement:\r
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