document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=625578>Question 625578</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a bank loaned out $18,000, part of it at the rate of 6% and the rest at 14%. If the interest received in one year totaled $2,000, how much was loaned at 6%?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #393654 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=393654\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a bank loaned out $18,000, part of it at the rate of 6% and the rest at 14%. If the interest received in one year totaled $2,000, how much was loaned at 6%? <BR>\n" );
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document.write( "Let x = amount ($) loaned at 6%<BR>\n" );
document.write( "then<BR>\n" );
document.write( "18000-x = amount ($) loaned at 14%<BR>\n" );
document.write( ".<BR>\n" );
document.write( ".06x + .14(18000-x) = 2000<BR>\n" );
document.write( ".06x + 2520-.14x = 2000<BR>\n" );
document.write( "2520-.08x = 2000<BR>\n" );
document.write( "-.08x = -520<BR>\n" );
document.write( "x = $6500  (answer)<BR>\n" );
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