document.write( "Question 625616: find the equation of straight line in the standard form.\r
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document.write( "gradient = -3 ,, graph passing through (5,1) \n" );
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Algebra.Com's Answer #393651 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! find the equation of straight line in the standard form.\r \n" ); document.write( "\n" ); document.write( "gradient = -3 ,, graph passing through (5,1) \n" ); document.write( ". \n" ); document.write( "gradient is the slope \n" ); document.write( "standard form is: Ax + By = C \n" ); document.write( ". \n" ); document.write( "Plug the given info into the \"point-slope\" form: \n" ); document.write( "y - y1 = m(x - x1) \n" ); document.write( "y - 1 = -3(x - 5) \n" ); document.write( "y - 1 = -3x + 15 \n" ); document.write( "y = -3x + 16 \n" ); document.write( "3x + y = 16 (this is what they're looking for)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |