document.write( "Question 625616: find the equation of straight line in the standard form.\r
\n" ); document.write( "\n" ); document.write( "gradient = -3 ,, graph passing through (5,1)
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Algebra.Com's Answer #393651 by nerdybill(7384)\"\" \"About 
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find the equation of straight line in the standard form.\r
\n" ); document.write( "\n" ); document.write( "gradient = -3 ,, graph passing through (5,1)
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\n" ); document.write( "gradient is the slope
\n" ); document.write( "standard form is: Ax + By = C
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\n" ); document.write( "Plug the given info into the \"point-slope\" form:
\n" ); document.write( "y - y1 = m(x - x1)
\n" ); document.write( "y - 1 = -3(x - 5)
\n" ); document.write( "y - 1 = -3x + 15
\n" ); document.write( "y = -3x + 16
\n" ); document.write( "3x + y = 16 (this is what they're looking for)\r
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