document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=625523>Question 625523</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am solving for x. Square root of (5x+5)=x+1. \r<BR>\n" );
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document.write( "Thanks so much. If you can, can you try to type out all the steps because I am not sure how to solve this equation at all and I am going to be tested on this material on Wednesday and I really would like to learn how to do it. Thanks again! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #393622 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=393622\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> start with:<BR>\n" );
document.write( "sqrt(5x+5) = x+1<BR>\n" );
document.write( "square both sides of this equation to get:<BR>\n" );
document.write( "5x+5 = (x+1)^2<BR>\n" );
document.write( "simplify to get:<BR>\n" );
document.write( "5x+5 = x^2+2x+1<BR>\n" );
document.write( "subtract 5x and subtract 5 from both sides of the equation to get:<BR>\n" );
document.write( "0 = x^2-3x-4<BR>\n" );
document.write( "this is the same as:<BR>\n" );
document.write( "x^2-3x-4 = 0<BR>\n" );
document.write( "factor this quadratic equation to get:<BR>\n" );
document.write( "(x-4)*(x+1) = 0<BR>\n" );
document.write( "solve for x to get:<BR>\n" );
document.write( "x=4, x=-1<BR>\n" );
document.write( "both of these solutions are good as you will see when you substitute for x in the original equation using each in turn.<BR>\n" );
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