document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=625554>Question 625554</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i am stuck.. the problem is .35x+.25y=.3(8)<BR>\n" );
document.write( "x+y=8 \r<BR>\n" );
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document.write( "y=-x+8\r<BR>\n" );
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document.write( ".35x+.25(-x+8+.3<BR>\n" );
document.write( ".35x+.25x+2=2.4<BR>\n" );
document.write( ".6x=2.4-2\r<BR>\n" );
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document.write( "i have to solve using linear equations of substitution...HELP PLEASE<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #393612 by </B><A HREF=/tutors/aboutme.mpl?userid=Khukubabu><B>Khukubabu(5)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Khukubabu><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Khukubabu><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=393612\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .35x+.25y=.3(8)<BR>\n" );
document.write( "or, 35x+25y=2400 (multiplying both side 100)<BR>\n" );
document.write( "or, 35x-25x+200=2400<BR>\n" );
document.write( "or, 10x=2200<BR>\n" );
document.write( "or, x=220<BR>\n" );
document.write( "so, y=(-212)\r<BR>\n" );
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document.write( "I think, here, .3(8)=.3*8 </SPAN>\n" );
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